Q:

please someone help, really having trouble with it

Accepted Solution

A:
Answer:see explanationStep-by-step explanation:Note the differences in T are constant, that is55 - 49 = 61 - 55 = 67 - 61 = 73 - 67 = 79 - 73 = 85 - 79 = 91 - 85 = 6Since the first differences are constant then the relationship between time and Temperature is linear and the constant is a multiplier, that isT = 6t Β± c ← c is a constantConsider the values of T to determine ct = 8 β†’ T= 6 Γ— 8 = 48 β†’ require to add 1 for 49t = 9 β†’ T = 6 Γ— 9 = 54 β†’ require to add 1 for 55t = 10 β†’ T = 6 Γ— 10 = 60 β†’ require to add 1 for 61t = 11 β†’ T = 6 Γ— 11 = 66 β†’ require to add 1 for 67t = 12 β†’ T = 6 Γ— 12 = 72 β†’ require to add 1 for 73the result is similar for t = 13, 14, 15HenceT = 6t + 1 ← is the equation defining the relationship